Given an array nums
of distinct integers, return all the possible permutations. You can return the answer in any order.
Example 1:
Input: nums = [1,2,3] Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Example 2:
Input: nums = [0,1] Output: [[0,1],[1,0]]
Example 3:
Input: nums = [1] Output: [[1]]
Constraints:
1 <= nums.length <= 6
-10 <= nums[i] <= 10
- All the integers of
nums
are unique.
Idea:
Use DFS template
Solution:
/**
* @param {number[]} nums
* @return {number[][]}
*/
var permute = function(nums) {
let res = [];
let cur = [];
let len = nums.length;
let used = new Array(len).fill(false);
dfs(nums, len, res, cur, used);
return res;
}
function dfs(nums, len, res, cur, used) {
// exit recursive condition
if (cur.length === len) {
res.push(cur.concat());
return;
}
// possible solution
for (let i = 0; i < len; i++) {
// skip used integer
if (used[i]) continue;
// modify current state
used[i] = true;
cur.push(nums[i]);
dfs(nums, len, res, cur, used);
// recover current state
cur.pop();
used[i] = false;
}
}